Force floor: Difference between revisions

No change in size ,  21 May 2019
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{{Infobox Tile
{{Infobox Tile
|image cc1 = [[File:Force Floor N.png]]<br/>[[File:Force Floor W.png]][[File:Force Floor Random.png]][[File:Force Floor E.png]]<br/>[[File:Force Floor S.png]]
|image cc1 = [[File:Force floor N.png]]<br/>[[File:Force floor W.png]][[File:Force floor Random.png]][[File:Force floor E.png]]<br/>[[File:Force floor S.png]]
|image cc2 = [[File:Force Floor N.png]]<br />[[File:Force Floor W.png]][[File:Force-Floor-Random-CC2.gif]][[File:Force Floor E.png]]<br />[[File:Force Floor S.png]]
|image cc2 = [[File:Force floor N.png]]<br />[[File:Force floor W.png]][[File:Force-Floor-Random-CC2.gif]][[File:Force floor E.png]]<br />[[File:Force floor S.png]]
|cc1 = Yes
|cc1 = Yes
|cc2 = Yes
|cc2 = Yes
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A demonstration of the properties of force floors can be found in the diagram below:
A demonstration of the properties of force floors can be found in the diagram below:


[[File:Force floor demo.png]]
[[File:Force Floor demo.png]]


If Chip steps R, he will always slide >R, but can then step in any legal direction off [3, 1]. Assuming he steps U, he is then subject to a >L move, and can then override [2, 0]. However, since [1, 0] is an east force floor, Chip will not be able to reach the exit unless he has [[suction boots]]. Chip also cannot exit by starting with an U move, because his last move was voluntary.
If Chip steps R, he will always slide >R, but can then step in any legal direction off [3, 1]. Assuming he steps U, he is then subject to a >L move, and can then override [2, 0]. However, since [1, 0] is an east force floor, Chip will not be able to reach the exit unless he has [[suction boots]]. Chip also cannot exit by starting with an U move, because his last move was voluntary.
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